2[d-(2d+19)+18]=2(d+1)

Solution for 2[d-(2d+19)+18]=2(d+1) equation:

Simplifying
2[d + -1(2d + 19) + 18] = 2(d + 1)

Reorder the terms:
2[d + -1(19 + 2d) + 18] = 2(d + 1)
2[d + (19 * -1 + 2d * -1) + 18] = 2(d + 1)
2[d + (-19 + -2d) + 18] = 2(d + 1)

Reorder the terms:
2[-19 + 18 + d + -2d] = 2(d + 1)

Combine like terms: -19 + 18 = -1
2[-1 + d + -2d] = 2(d + 1)

Combine like terms: d + -2d = -1d
2[-1 + -1d] = 2(d + 1)
[-1 * 2 + -1d * 2] = 2(d + 1)
[-2 + -2d] = 2(d + 1)

Reorder the terms:
-2 + -2d = 2(1 + d)
-2 + -2d = (1 * 2 + d * 2)
-2 + -2d = (2 + 2d)

Solving
-2 + -2d = 2 + 2d

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-2d' to each side of the equation.
-2 + -2d + -2d = 2 + 2d + -2d

Combine like terms: -2d + -2d = -4d
-2 + -4d = 2 + 2d + -2d

Combine like terms: 2d + -2d = 0
-2 + -4d = 2 + 0
-2 + -4d = 2

Add '2' to each side of the equation.
-2 + 2 + -4d = 2 + 2

Combine like terms: -2 + 2 = 0
0 + -4d = 2 + 2
-4d = 2 + 2

Combine like terms: 2 + 2 = 4
-4d = 4

Divide each side by '-4'.
d = -1

Simplifying
d = -1